The smallest integer that can be represented by an 8-bit number in 2's complement form is?

 

Answer:   -128

The range of numbers that can be represented by n-bits in 2’s complement form is

(-2)^n-1 to (2^n-1) -1

So, the smallest number is (-2)^n-1  à (-2)^8-1 à (-2)⁷  = -128

The largest number is (2^n-1) – 1 à (2⁷) – 1 = 127